Reverse – Vault door 6

Vault door 6 - 350pt


This vault uses an XOR encryption scheme. The source code for this vault is here:


If X ^ Y = Z, then Z ^ Y = X. Write a program that decrypts the flag based on this fact.


Again, there’s a list of numbers meant to be read as ASCII codes. The only difference from Level 4 is that you have to xor every number with 0x55 before decoding.


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